Home
Class 12
PHYSICS
A compound microscope has an objective o...

A compound microscope has an objective of focal length `2.0 cm` and an eye-piece of focal length `6.25cm` and distance between the objective and eye-piece is `15cm`. If the final image is formed at the least distance vision `(25 cm)`, the distance of the object form the objective is

A

1.5cm

B

2.5cm

C

3.0cm

D

4.0cm

Text Solution

Verified by Experts

The correct Answer is:
B

`(-1)/mu_(0) + 1/v_(0) =1/f_(0)` (find `v_(0)`),`(-1)/u_(0)=1/f_(e)` find `u_(e)`
`m_(0)=v_(0)/u_(0),m_(e)`
Promotional Banner

Topper's Solved these Questions

  • RAY OPTICS AND OPTICAL INSTRAUMENTS

    NARAYNA|Exercise EXERCISE-2 (H.W)(OPTICAL INSTRUMENTS ( TELESCOPES ))|5 Videos
  • RAY OPTICS AND OPTICAL INSTRAUMENTS

    NARAYNA|Exercise EXERCISE- 3|33 Videos
  • RAY OPTICS AND OPTICAL INSTRAUMENTS

    NARAYNA|Exercise EXERCISE-2 (H.W)(DEFECTS OF THE EYE)|3 Videos
  • NUCLEI

    NARAYNA|Exercise ASSERTION & REASON|5 Videos
  • SEMI CONDUCTOR DEVICES

    NARAYNA|Exercise Level-II (H.W)|36 Videos

Similar Questions

Explore conceptually related problems

A microscope has an objective of focal length 1.5 cm and eye piece of focal length 2.5 cm . If the distance between objective and eyepiece is 25 cm . What is the approximate value of magnification produced for relaxed eye ?

A compound microscope has an objective of focal length 2 cm and eye-piece of focal length 5 cm. The distance between the two lenses is 25 cm. If the final image is at a distance of 25 cm from the eye-piece, find the magnifying power of the microscope. What would be the magnifying power if the microscope were reversed ?

A compound microscope has an eye piece of focal length 10 cm and an objective of focal length 4 cm . Calculate the magnifcation, if an object is kept at a distance of 5 cm from the objective so that final image is formed at the least distance vision (20 cm)

A compound microscope has an objective lens of 1.0 cm focal length and an eye-piece of 2.5 cm of focal length. When the object is placed at 1.1 cm from the objective, the final image is at the least distance of direct vision. Thus, the magnification produced is