The frequency of a light wave in a material is `2xx10^(14)Hz` and wavelength is `5000 Å`. The refractive index of material will be

Options

A. 1.5
B. 3
C. 1.33
D. 1.4

Answer

2

Explanation

`:. mu = ( "velocity of light in vacuum" (c ))/("velocity of light in medium" (v))`
`:. V=V lambda = 2xx10^(14)xx5000xx10^(-10)`
In the medium v = `10^(8)`m/s
`:. Mu = (v_(vac))/v_(med) = (3xx10^(8))/(10^(8))` = 3