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In an astronomical telescope in normal a...

In an astronomical telescope in normal adjustment a straight black line of length `L` is drawn on inside part of objective lens. The eye piece forms a real image of this line. The length of this image is `I`. The magnification of the telescope is

A

`L/I`

B

`L/I + I`

C

`L/I - I`

D

`(L+I)/(I-I)`

Text Solution

Verified by Experts

The correct Answer is:
1
`L/f_(0)=I/f_(e)`
`:. f_(0)/f_(e)=I/l`
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