The angle of incidence for a ray of light at a refracting surface of a prism is `45^(@)`. The angle of prism is `60^(@)`. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are `:`

Options

A. `45^(@),1/2`
B. `30^(@),sqrt2`
C. `45^(@),sqrt2`
D. `30^(@),1/sqrt2`

Answer

2

Explanation

`delta_(min)=30^(@)`
`mu = (sin((delta_(min) + A))/2)/(sin (A/2)) = (sin 45)/(sin30)`
`mu = (1//sqrt2)/(1//2) = sqrt2`
Hence (2) is correct option.