Yellow light with wavefront 0.5` mum` is air surface refraction in a medium in which velocity of light is `2xx10^(-8)m//s`. Then the wavelength of the light in the medium would be .

Explanation

`(lambda_(1))/(lambda_(2))=(v_(1))/(v_(2))`
Here, `lambda_(1) = 0 . 5 mu m , v_(1) = 3 xx 10^(8) m//s`
`lambda_(2) = ? (X) , v_(2) = 2 10^(8) m//s`
`(0.5)/(X) = (3 xx 10^(8))/(2 xx 10^(8))`
`rArr x = 0 . 33 mu m `
Note : The frequency remains unchanged .