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The fringe width at a distance of 50 cm ...

The fringe width at a distance of 50 cm from the slits in Young's experiment for light of wavelength `6000 Å` is `0.048cm`. The fringe width at the same distance for `lambda = 5000 Å` will be

A

0 . 04 cm

B

0 . 4 cm

C

0 . 14 cm

D

0 . 45 cm

Text Solution

Verified by Experts

The correct Answer is:
A
`beta = (lambdaD)/(d)`
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