Home
Class 12
PHYSICS
Two point sources distant 0.1 meter away...

Two point sources distant `0.1` meter away viewed by a telescope. The objective is covered by a screen having a hole of 1 mm width. If the wavelength of the light used is `6500 Å` , then maximum distance at which the two sources are seen just resolved, will be nearly

A

125.0 m

B

164 m

C

131 m

D

144 m

Text Solution

Verified by Experts

The correct Answer is:
A

`theta = (1.22 lambda)/(a)`
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 1 (H.W) Polarisation|5 Videos
  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 2 (C . W) Interference|13 Videos
  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 1 (H.W) Diffraction|3 Videos
  • SEMICONDUCTOR ELECTRONICS

    NARAYNA|Exercise ADDITIONAL EXERCISE (ASSERTION AND REASON TYPE QUESTIONS :)|19 Videos

Similar Questions

Explore conceptually related problems

Two points sources distance 0.1 m are viewed by a telescope. The objective is covered by ascreen having a hole of 1 mm widht. If the wavelenghts of light used is 5000Å, the the maximum distance at which the two sources are seen just resolved, will be

Two point sources distant 0.1 meter away viewed by a telescope. The objective is covered by a terlescope. The objective is covered by a screen having a hole of 1 mm width. If the wavelength of the light used is 6500 Å , then maximum distance at which the two sources are seen just resolved, will be nearly

Two luminous point sources separated by a certain distance are at 10 km from an observer. If the aperture of his eye is 2.5xx10^(-3)m and the wavelength of light used is 500 nm, the distance of separation between the point sources just seen to be resolved is

Two stars are situated at a distance of 8 light years from the earth. These are to be just resolved by a telescope of diameter 0.25 m. If the wavelength of light used is 5000 Å, then the distance between the stars must be

In YDSE, the distance between the slits is 1 m m and screen is 25cm away from the slits . If the wavelength of light is 6000 Å , the fringe width on the secreen is

The distance between two coherent sources is 0.1 mm. The fringe-width on a screen 1.2 m away from the source is 6.0 mm. The wavelength of light used is

In Fresnel's biprism experiment the width of 10 fringes is 2cm which are formed at a distance of two 2meter from the silt .If the wavelength of light is 5100Å then the distance between two coherent sources will be

The semi vertical angle of the cone of the rays of light incident on the objective of a microscope is 20^(@) . If the wavelength of incident light is 6000Å , calculate the smallest distance between two points which can be just resolved.