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The I^(st) diffraction minimum due to si...

The `I^(st)` diffraction minimum due to single slit diffraction is `theta`, for a light of wave length `5000 Å` . If the width of the slit si `1xx10^(-4) cm` then the value of `theta`

A

`30^(0)`

B

`45^(0)`

C

`60^(0)`

D

`15^(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
`a sin theta = n lambda`
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Knowledge Check

  • The I^(st) different minimum due to single slit diffraction is theta , for a light of wave length 5000 Å . If the width of the slit si 1xx10^(-4) cm then the value of theta

    A
    `30^(@)`
    B
    `45^(@)`
    C
    `60^(@)`
    D
    `15^(@)`

  • The first diffraction minima due to a single slit diffraction is at theta=30^(@) for a light of wavelength 5000Å The width of the slit is

    A
    `5xx10^(-5)cm`
    B
    `10xx10^(-5)cm`
    C
    `2.5xx10^(-5)cm`
    D
    `1.25xx10^(5)cm`

  • Frist diffraction minima due to of a single slit diffraction is at theta = 30^(@) for a light of wavelength 6000 Å . The width of slits is

    A
    `1xx10^(-6)cm`
    B
    `1.2xx10^(-6)m`
    C
    `2xx10^(-6)cm`
    D
    `2.4xx10^(-6)m`

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