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In a Young's double slit experiment, D e...

In a Young's double slit experiment, D equals the distance of screen and d is the separation between the slits. The distance of the nearest point to the central maximum where the intensity is same as that due to a single slit is equla to

A

`(D lambda)/(d)`

B

`(D lambda)/(2d)`

C

`(D lambda)/(3d)`

D

`( 2 D lambda)/(d)`

Text Solution

Verified by Experts

The correct Answer is:
C
`I = 4 I_(0) "cos" ^(2) (phi)/(2) rArr I_(0) = 4I_(0) "cos"^(2) (phi)/(2)`
`phi = (2pi)/(3), phi = (2pi)/(lambda) Delta x, "But" Delta x = (yd)/(D)`
`rArr (yd)/(D) = (lambda)/(3) rArr y = (lambda D)/(3d)`
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