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Find the frequency of revolution of the ...

Find the frequency of revolution of the electron in the first orbit of H-atom

A

`6xx10^(14)Hz`

B

`6.6xx10^(10)Hz`

C

`6.6xx10^(-10)Hz`

D

`6.6xx10^(15)Hz`.

Text Solution

Verified by Experts

The correct Answer is:
D
`T=(2pi r)/( V) ` where `V =(3xx10^(8))/(137), r =0.53xx 10^(-10)m`
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Knowledge Check

  • Find the frequency of revolution of the electron in the first stationary orbit of H -atom

    A
    `6xx10^(14)Hz`
    B
    `6.6xx10^(10)Hz`
    C
    `6.6xx10^(-10)Hz`
    D
    `6.6xx10^(15)Hz`

  • In a hydrogen atom, the binding energy of the electron in the ground state is E_(1) then the frequency of revolution of the electron in the nth orbit is

    A
    `2E_(1)//nh`
    B
    `2E_(1)n//h`
    C
    `E_(1)//nh`
    D
    `E_(1)n//h`

  • In a hydrogen atom, the binding energyo of the electron in the gound state is E_(1) . Then the frequecny of revolution of the electron in the nth orbit is

    A
    `(2E_(1))/(n^(3)h)`
    B
    `(2E_(1)n^(3))/(h)`
    C
    `sqrt((2mE_(1))/(n^(3)h))`
    D
    `(E_(1)n^(2))/(h)`

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