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Let the potential energy of the hydrogen...

Let the potential energy of the hydrogen atom in the ground state be zero . Then its energy in the excited state will be

A

10.2eV

B

13.6eV

C

23.8eV

D

27.2eV

Text Solution

Verified by Experts

The correct Answer is:
C
`P.E_(2) =-(27.2)/(4)+27.2 =20.4eV`
`K.E_(1) =13.6eV, K.E_(2)=3.4eV`
`therefore T.e_(2)=20.4+3.4 =23.8eV`.
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