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An alpha-particle accelerated through V ...

An alpha-particle accelerated through `V` volt is fired towards a nucleus . Its distance of closest approach is . `r` If a protons is accelerated through the same potential and fired towards the same nucleus , the distance of closest approach of proton will be .

A

r

B

2r

C

r/2

D

r/4

Text Solution

Verified by Experts

The correct Answer is:
A
`KE=PE rArr q_(1) V=(1)/(4pi epsilon_0)(q_(1)q_(2))/( r)`
Independent of charge of the particle projected
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