An alpha nucleus of energy `(1)/(2)m nu^(2)` bombards a heavy nucleus of charge `Ze` . Then the distance of closed approach for the alpha nucleus will be proportional to
An alpha nucleus of energy (1)/(2)m nu^(2) bombards a heavy nucleus of charge Ze . Then the distance of closed approach for the alpha nucleus will be prpportional to
When an alpha particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as
When an alpha- particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on m as :
When an a-particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze', its distance of closest approach from the nucleus depends on v as:
An alpha - particle after passing through a potential difference of V volts collides with a nucleus . If the atomic number of the nucleus is Z then the distance of closest approach of alpha – particle to the nucleus will be
An alpha - particle after passing through a potential difference of V volts collides with a nucleus . If the atomic number of the nucleus is Z then the distance of closest approach of alpha – particle to the nucleus will be
Calculate the energy of an alpha -particle whose distance of closest approach with the gold nucleus is 29.5 fermi.
