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Electron in hydrogen atom first jumps fr...

Electron in hydrogen atom first jumps from third excited state to second excited state and then form second excited state to first excited state. The ratio of wavelength `lambda_(1): lambda_(2)` emitted in two cases is

A

`(7)/(5)`

B

`(27)/(20)`

C

`(27)/(5)`

D

`(20)/(7)`

Text Solution

Verified by Experts

The correct Answer is:
D
According to Rydberg formula `(1)/(lambda)= R [(1)/(n_(f)^(2))- (1)/(n_(i)^(2))]`
In first case , `n_(f)=3n_(i)=4`
In second case `n_(f) =2 n_(i) =3`.
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