If an electron in a hydrogen atom jumps from the `3rd` orbit to the `2nd` orbit, it emits a photon of wavelength `lambda`. When it jumps form the `4th` orbit to the `3dr` orbit, the corresponding wavelength of the photon will be

Options

A. `(20)/(7)lambda`
B. `(20)/(13)lambda`
C. `(16)/(25)lambda`
D. `(9)/(16)lambda`

Answer

A

Explanation

Transition : `3 to 2 rArr ` Wavelength `lambda`.
Transition : `4 to 3 rArr` Wavelength `lambda= ?`
`(1)/(lambda)= R [(1)/(n_(f)^(2))-(1)/(n_(i)^(2))]` then `rArr (lambda)/(lambda) =(20)/(7)`.