Consider a hydrogen-like atom whose energy in nth excited state is given by
`E_(n) = (13.6 Z^(2))/(n^(2))`
When this excited makes a transition from excited state to ground state , most energetic photons have energy
`E_(max) = 52.224 eV`. and least energetic photons have energy
`E_(max) = 1.224 eV`
Find the atomic number of atom and the intial state or excitation.

Options

A. Z=2,n=5
B. Z=2,n=4
C. Z=3,n=6
D. Z=4,n=6

Answer

A

Explanation

Maximum energy is liberated for transition `E_(b) to 1` and minimum energy for `E_(n) to E_(n-1)`
Hence `Delta E =(Rhc)Z^(2) [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` .