When the electron in a hydrogen atom jumps from the second orbit to the first orbit , the wavelength of the radiation emitted is `lamda` . When the electron jumps from the third orbit to the first orbit , of the same atom , the wavelength of the emitted radiation would be

Options

A. `(9)/(4)lambda`
B. `(4)/(9)lambda`
C. `(27)/(32)lambda`
D. `(32)/(27)lambda`

Answer

C

Explanation

`(1)/(lambda)= RZ^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`