The ratio of the largest to shortest wavelength in Balmer series of hydrogen spectra is,

Options

A. `(25)/(9)`
B. `(17)/(6)`
C. `(9)/(5)`
D. `(5)/(4)`.

Answer

C

Explanation

`(1)/(lambda_("max"))= RZ^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` Where `n_(1) =2, n_(2) =3`
`(1)/(lambda_("min"))= RZ^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` Where `n_(1) =2 , n_(2) =alpha`.