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The wave number of energy emitted when e...

The wave number of energy emitted when electron jumps from fourth orbit to second orbit in hydrogen in `20,497cm^(-1)`. The wave number of energy for the same trasition in `He^(+)` is

A

`5.099 cm^(-1)`

B

`20,497 cm^(-1)`

C

`40,994 cm^(-1)`

D

`81,988 cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
` overline(v) = RZ^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2))), overline(v) alpha Z^(2)`
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