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The binding energy of an electron in the...

The binding energy of an electron in the ground state of He atom is `E_(0)=24.7eV`. The energy required to remove both the elements from the atom is

A

24.6eV

B

79.0eV

C

54.4eV

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

The total energy required to make the electron free from nucleus is the sum of the energy required to separate the electrons from the influence of each other and the energy required to separate the electrons from the influence of nucleus,i.e., Total required energy = BE of electron in He atom + ionization energy of He atom
`= (24.6+13.6xx2^2)eV`
`=(24.6 +54.4)e V =79eV`
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