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The radius of the oxygen nucleus .(8)^(...

The radius of the oxygen nucleus `._(8)^(16)O` is `2.8 xx 10^(-15)m`. Find the radius of lead nucleus `._(82)^(205)Pb`.

Text Solution

Verified by Experts

`R_(0) =2.8 x 10 ^(15) m, A_(0) = 16, A _(Pb) = 205`
We know that `R prop A ^(1//3)`
`(R_(0))/( R _(Pb))=((A_(0))/(A _(Pb)))^(1//3) implies (2.8 xx 10 ^(-15))/(R _(Pb))= ((16)/(205)) ^(1//3)`
`R _(Pb) =6.55 x 10^(-15)m.`
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