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Find the binding energy of .(26)^(56)Fe....

Find the binding energy of `._(26)^(56)Fe`. Atomic mass of Fe is 55.9349u and that of Hydrogen is 1.00783u and mass of neutron is 1.00876u.

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Mass of the hydrogen atom `m _(H) = 1.00783u,` Mass of neutron `m _(n) = 1. 00867u,` Atonmic number of iron `Z = 26,` mass number of iron `A = 56,` Mass of iron atom `M _(a) = 55.9349u`
Mass defect `Delta m = [Zm _(H)+ (A-Z)m_(n) ]-M_(a)`
`= [26 x 1.00783 + (56-26) xx 1.00867] u 55.93493u=0.5287u.`
`therefore` Binding energy `= (Delta m) c^(2) = (0.52878)c^(2)`
`= (0.52878) (931.5MeV) = 492.55MeV`
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