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Calculate the energy released by fission...

Calculate the energy released by fission from 2g of `._(92)^(235)U` in kWh. Given that the energy released per fission is 200 MeV.

Text Solution

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mass of uranium = 2g
Energy released per fission = 200 MeV
`=200 x 10 ^(6) x 1.6 x 10 ^(-19) = 3.2 x 10 ^(-11) J`
Number of atoms in 2 gram of uranium is
`n = ( 2 xx 6. 023xx 10 ^(23))/(235) = 5.125 xx 10 ^(21)` atoms
Total energy released = No. of atom x energy released per fission
`= 5.125 x 10 ^(21) x 3.2 xx 10 ^(-11) = 16.4 xx 10 ^(10J`
`therefore` Energy in `Kwh = (16.4 xx 10 ^(10))/( 36 xx 10 ^(5)) Kwh`
`= 0. 455 xx 10 ^(5) Kwh= 4.55 xx 10 ^(4) Kwh`
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