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200 MeV energy is released when one nnuc...

200 MeV energy is released when one nnucleus of `.^(235)U` undergoes fission. Find the number of fissions per second required for fissions per second required for producing a power of 1 megawatt.

Text Solution

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Energy released `= 200 MeV`
`= 200 x 10 ^(6) x 1.6 xx 10 ^(-19) = 3.2 x 10 ^(-11)J`
`P =1` meag watt `= 10 ^(6) ` watts.
No. of fissions per second
`(n) = ("Total energy")/("Energy per fission")`
`n = ( 10 ^(6))/(3.2 xx 10 ^(-11))= 3.125 xx 10 ^(6)` Fissions
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