How much `.^(235)U` is consumed in a day in an atomic powder house operating at `400 MW`, provided the whole of mass `.^(235)U` is converted into energy?

Explanation

Power `= 400 MW = 400 x 10 ^(6) W`
time 1 day = 86, 400 s.
Energy produced, E = power `xx` time `= 400 xx 10 ^(6) xx 86,400= 3.456 xx 10 ^(13) J.`
As the jwhole of mass is converted into energy but Einstin.s mass-energy relation.
` E = Mc ^(2)`
` (E)/(c ^(2)) = (3.456 xx 10 ^(13))/((3 xx 10 ^(8))^(2))= 3. 84 xx 10 ^(-4) kg = 0.384g.`