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The desity of a nucleus in which mass of...

The desity of a nucleus in which mass of each nucleon is `1.67xx10^(-27)kg` and `R_(0)=1.4xx10^(-15)m` is

A

`1.453 xx 10 ^(7) kg//m^(3)`

B

`1.453 xx 10 ^(16) kg//m^(3)`

C

`1.453 xx 10 ^(21) kg //m^(3)`

D

`1.453 xx 10 ^(21) kg//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`D = (Am)/((4)/(3) pi R ^(3)) = (3 Am )/( 4pi (R_(0) A ^((1)/(3)))^(3))= (3 Am )/( 4 pi R _(0) ^(3) A)= (3m)/( 4 pi R _(0)^(3))`
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Assuming that protons and neutrons have equal masses, calculate how many times nuclear matter is denser than water. Take mass of a nucleon =1.67xx10^(-27)kg and R_(0)=1.2xx10^(-15)m .

How many protons weight 5kg? The mass of a proton is 1.67xx10^(-27)kg .

Knowledge Check

  • Rest mass of 1 mole neutrons (m_(n)=1.675xx10^(-27)kg) is:

    A
    `1.8xx10^(-3)kg`
    B
    `1.008xx10^(-4)kg`
    C
    `1.08xx10^(-3)kg`
    D
    `1.008xx10^(-3)kg`

  • Given the mass of iron nucleus as 55.85u and A = 56, the nuclear density is (u = 1.66 xx 10 ^(-27) kg, r = 1.2 xx 10 ^(-15)m )

    A
    `1.29 xx 10 ^(-7)kgm^(-3)`
    B
    `2.29 xx 10 ^(17 kgm ^(-3))`
    C
    `2.29 xx 10 ^(-7 kgm ^(-3))`
    D
    `1.29 xx 10 ^(-27 kgm ^(-3))`

  • Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron = 1.6725 xx 10^(-27) kg mass of proton = 1.6725 xx 10^(-27) kg mass of electron = 9 xx 10^(-31) kg )

    A
    `0.73 MeV`
    B
    `7.10 MeV`
    C
    `6.30 MeV`
    D
    `5.4 MeV`

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    Calculate the nuclear mass density of ._92U^(238) . Given R_0=1.5 fermi and mass of each nucleon is 1.67xx10^(-27)kg .

    Calculate the ratio between the wavelength of an electron and a proton, if the proton is moving at half the velocity of the electron (mass of the proton =1.67xx10^(-27)kg , mass of the electron =9.11xx10^(-2)m .

    Calculate the ratio between the wavelength of an electron and a proton if the proton is moving with half the velocity of electron (mass of proton = 1.67 xx 10^(-27)kg and mass of electron = 9.11 xx 10^(-31) kg )

    Assume that a neutron breaks into a proton and an electron. The energy released during this process is (mass of neutron = 1.6725 xx 10^(-27) kg, mass of proton = 1.6725 xx 10^(-27) kg , mass of electron = 9 xx 10^(-31) kg)

    The order of magnitude of density of urnaitum nucleus is: (m_("nucleus") = 1.67xx10^(-27)kg)

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