After a certain lapse of time, fraction ...

After a certain lapse of time, fraction of radioactive polonium undecayed is found to be `12.5%` of the initial quantity. What is the duration of this time lapsed if the half life of polonium is 138 days ?

A

414 days

B

407 days

C

421 days

D

410 days

Text Solution

Verified by Experts

The correct Answer is:

A

`(dN)/(dt) = lamda N,` here N = avagadrono /238, ` lamda = 0.693 //T_((1)/(2))`

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