The amount of energy released in the fusion of two `._(1)H^(2)` to form a `._(2)He^(4)` nucleus will be {Binding energy per nucleon of `._(1)He^(2)=1.1 MeV` Binding energy per nucleon of `._(2)He^(4)=7 MeV`]

Options

A. `8.1 MeV`
B. `5.9 MeV`
C. `23.6 MeV`
D. `2 MeV`

Answer

C

Explanation

`"" _(1) H ^(2) + "" _(1) H ^(2) to "" _(2) He ^(4) + Q`
E= B.E. of products- B.E. of reactants
`=4 (7) -4 (1.1) = 23.6 MeV`