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The miniumum amount of energy released i...

The miniumum amount of energy released in annihilation of electron-Positron is

A

`1.02 MeV`

B

`0.58 MeV`

C

`185 MeV`

D

`200 MeV`

Text Solution

Verified by Experts

The correct Answer is:
A
`0.51 MeV + 0.51 MeV = 1. 02 MeV`
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