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Half life of a radio active element is 5...

Half life of a radio active element is `5 min`. `10 sec`. Time taken for `90%` of it to disintergrate is nearly

A

100 min

B

1000 sec

C

`10^(4)` sec

D

`10^(4)` min

Text Solution

Verified by Experts

The correct Answer is:
B
`t = (t _((1)/(2)))/(log 2) log ((N _(0))/(N))`
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