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4 grams of radioactive substance A left ...

`4` grams of radioactive substance `A` left `1//2 gm` after some time . `1` gram of another radioactive substance `B` left `1//4 gm` in the same period, If half life of `B` is `2` hours, the half life of `A` is ( in hours)

A

`3//4`

B

`4//3`

C

`1//4`

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
B

`W = (W _(0))/(2 ^(n)),` no of half lives `n = (t)/(t _(1//2))`
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