A proton with kinetic energy `K`, strikes another proton at rest. If the collision is head-on, find the correct graph between `K` and the distance of closest approach, `r`.

Options

A.
B.
C.
D.

Answer

C

Explanation

At closest aproach, both protons will be moving with same velocity.
`Delta K. E = 1/2 mv _(0) ^(2) -2. (1)/(2) m((v _(0))/(2)) ^(2) = (e ^(2))/(4pi in _(0) r)`
`1/4 mv _(0) ^(2) = (2 pi in _(0)=` constnat, ` K alpha (1)/(r)`