Suppose a pure Si crystal has `6xx10^(28)` atoms `m^(-3)`. It is doped by 1ppm concentration of pentavalent As. Calculate the number of electrons and holes, Given that `n_(i)=0.5xx10^(16)m^(-3)`

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant concepts of semiconductor physics.

### Step 1: Understand the given data
- The number of silicon atoms in the crystal, \( N_{Si} = 6 \times 10^{28} \, \text{atoms/m}^3 \)
- The concentration of dopant (pentavalent arsenic) is given as 1 ppm.
- The intrinsic carrier concentration of silicon, \( n_i = 0.5 \times 10^{16} \, \text{m}^{-3} \)

### Step 2: Calculate the number of dopant atoms
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