The current in the forward bias is unknown to be more (~mA) than the current in the reverse bias (`~muA`). What is the reason then to operate the photo diodes in reverse bias ?

Explanation

Consider the case of an n-type semiconductor. The majority carrier density (n) is considerably larger than the cory hole density `p(ngtgtp)` On illumination, let the excess electrons and holes generated be `DeltanandDeltap`, respectively
`n^(1)=n+Deltan" "," p^(1)=p+Deltap`
Here `n^(1)andp^(1)` are the electron and hole concentrations at a particular animation and n and p are carrier concentration when there is no illumination. Remember `Deltan=Deltapandngtgtp`. Herce, the fractional change in the majority carriers (i.e., `Deltan//n`) would be much less than that in the minority carrier dominated reverse bias current is more easily measurable than the fractional change in the forward bias current. Hence, photodiodes are preferably used in the reverse bias condition for measuring light intensity