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In an npn transistor the base the collec...

In an `npn` transistor the base the collector currents are `100 muA` and `9 mA` respectively. Then the emitter current will be

A

`9.1mA`

B

`18.2mA`

C

`3.9muA`

D

`18.2muA`

Text Solution

Verified by Experts

The correct Answer is:
A
`I_(e)=I_(b)+I_(c),`
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Knowledge Check

  • In an npn transistor the base the collector currents are 100 muA and 9 muA respectively. Then the emitter current will be

    A
    `9.1 mA`
    B
    `18.2 mA`
    C
    `3.91 mA`
    D
    `18.2 mu A`

  • In an NPN transistor the values of base current and collector current are 100muA and 9mA respectively the emitter current will be-

    A
    9.1 mA
    B
    18.2 mA
    C
    `9.1muA`
    D
    `18.2muA`

  • In a P-N-P transistor, the collector current is 10 mA . If 90% of the holes reach the collector, then emitter current will be :

    A
    `13 mA`
    B
    `12 mA`
    C
    `11 mA`
    D
    `10 mA`

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