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For a transistor beta = 40 and I(B) = 25...

For a transistor `beta = 40` and `I_(B) = 25 muA`. Find the value of `I_(E)`.

A

1 mA

B

`1.025 mA`

C

2 mA

D

`1.2 mA`

Text Solution

Verified by Experts

The correct Answer is:
B
`beta=(I_(C))/(I_(B)) rArr I_(C)=betaI_(B)=40xx25xx10^(-6) and I_(B)=I_(E)+I_(C)`
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