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Assume that the number of hole-electron ...

Assume that the number of hole-electron pair in an intrinsic semiconductor is proportional to `e^(- Delta E//2KT)`. Here `Delta E` = energy gap and `k=8.62 xx 10^(-5) eV//"kelvin"`
The energy gap for silicon is `1.1 eV`. The ratio of electron hole pairs at`300 K` and `400 K` is :

A

`e^(-531)`

B

`e^(5)`

C

e

D

`e^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(N_(1))/(N_(2))=(e^(-DeltaE//2KT_(1)))/(e^(-DeltaE//2KT_(2)))`
`=e^((DeltaE)/(2K)((1)/(T_(2))-(1)/(T_(1))))=(1.1)/(e^(2xx8.62xx10^(-5)))((1)/(400)-(1)/(300))`
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