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For a CE-transistor amplifier, the audio...

For a `CE`-transistor amplifier, the audio signal voltage across the collector resistance of `2k Omega` is `2V`. Suppose the current amplification factor of the transistor is `100`. Find the input signal voltage and base current, if the base resistance is `1 k Omega`.

A

0.02V

B

0.01V

C

0.03V

D

0.04V

Text Solution

Verified by Experts

The correct Answer is:
B
Here, `v_(0)=2V,beta=100,`
`R_(C)` (collector resistance) `=2kOmega,R_(B)=1kOmega`
As `A_(v)=(v_(0))/(v_(1))=beta((R_(C))/(R_(B))),v_(i)=v_(0)(R_(B)/(R_(C)))((1)/(beta))`
`=(2V)((1kOmega)/(2kOmega))((1)/(100))=0.01V`
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Knowledge Check

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