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In an n-p-n transistor 10^(10) electrons...

In an n-p-n transistor `10^(10)` electrons enter the emitter in `10^(-6)`s. If 2% of the electrons are lost in the base, find the current transfer ratio and the current amplification factor.

A

0.98, 49

B

1.96, 98

C

0.49, 98

D

1.96, 49

Text Solution

Verified by Experts

The correct Answer is:
A
`I_(e)=(n_(e)xxe)/(t)andI_(c)=(n_(c)xxe)/(t)`
`alpha=(I_(c))/(I_(e))`
`beta=(alpha)/(1-alpha)`
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