A n-p-n transistor is connected to common emitter configuration in a given amplifier. A load resistance of 800 `Omega` is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 `Omega` the voltage gain and the power gain of the amplifier will respectively be

Options

A. 4, 3.84
B. 3.69, 3.84
C. 4, 4
D. 4, 3,69

Answer

A

Explanation

Voltage gain =(current gain) `xx` (resistance gain)
Here, current gain `alpha=0.96`
Voltage gain for common base configuration
`A_(v)=alphaxx(R_(L))/(R_(P))=0.96xx(800)/(192)=4`
Power gain for common base configuration
`P_(v)=A_(v)xxalpha=4xx0.96=3.84`