The input resistance of a silicon transistor is `100 Omega`. Base current is changed by `40 muA` which results in a change in collector current by `2 mA`. This transistor is used as a common-emitter amplifier with a load resistance of `4k Omega`. The voltage gain of the amplifier is

Options

A. 2000
B. 3000
C. 4000
D. 1000

Answer

A

Explanation

We know
`V_(g)=betaxx(R_(L))/(R_(t))=(DeltaI_(C))/(DeltaI_(B))xx(R_(L))/(R_(t))" "("":.beta=(DeltaI_(C))/(DeltaI_(B)))`
`:.V_(g)=(2xx10^(-3))/(40xx10^(-6))xx(4xx10^(3))/(100)=2000`