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The electrical conductivity of a semicon...

The electrical conductivity of a semiconductor increases when electromagnatic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is `[hc=1242 eV nm]`

A

`0.7eV`

B

`0.5eV`

C

`0.6eV`

D

`1.1eV`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=(12375)/(lambda("in" Å))eV rArr (12375)/(24800)eV rArr =0.5eV`
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