The currect voltage relation of diode is given by `1=(e^(1000 V//T)-1) mA`, where the applied voltage V is in volt and the temperature T is in degree Kelvin. If a student makes an error measuring `+-0.01 V` while measuring the current of `5 mA` at `300 K`, what will be error in the value of current in mA?

Options

A. `0.5mA`
B. `0.05mA`
C. `0.2 mA`
D. `0.02 mA`

Answer

C

Explanation

`5=e^(1000(V)/(T))-1`
`rArr e^(1000(V)/(T))=6------(i)`
Again `I=e^(1000(V)/(T))-1`
`(dI)/(dV)=e^((1000)/(T)) (1000)/(T)`
`dI=(1000)/(T)e^((1000)/(T)V) dV`
Using (i)
`DeltaI=(1000)/(T)xx6xx0.01=(60)/(I)=(60)/(300)=0.2mA`