A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicualr to AC upto B, a distaance of 100m and looks at O and C again. Since O is very distant, the direction of BO is practically the same as AO, but he finds the line of sight of C shifted from the original line of sight by an angle `theta = 40^@ ( theta "is known as parallax").` Estimate the distance fo the tower C from his original position A.

Explanation

Parallax angle `theta= 40^(@), AB= AC tan theta`
`AC= (AB)/(tan theta)= (100m)/(tan 40^(@))`
`= (100m)/(0.8391)= 119m`.