In an experiment of simple pendulum, the errors in the measurement of length of the pendulum `(L)` and time period `(T)` are `3%` and `2%` respectively. The maximum percentage error in the value of `L//T^(2)` is

Explanation

`(DeltaL)/(L) xx 100=3%,(DeltaT)/(T) xx 100=2%`
Maximum percentage error in the value of
`(L)/(T^(2))=(DeltaL)/(L) xx 100+2 xx (DeltaT)/(T) xx 100=3+(2 xx 2)=3+4`
Maximum percentage error in the value of `(L)/(T^(2))=7%`