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The dimensionla formula for the product ...

The dimensionla formula for the product of two physical quantities `P` and `Q` is `[ML^(2) T^(-2)]`. The dimensional formula of `(P)/(Q)` is `[MT^(-2)]`. Then `P` and `Q` respectively are

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Give `P xx Q` has dimensions `ML^2 T^(-2)`
P/Q has dimensions `ML^0 T^(-2)`
Hence , (PQ) `(P/Q) = (ML^2 T^(-2)) (ML^0 T^(-2))`
`P^2 = M^2 L^2 T^(-4)`
`therefore P = ML^1 T^(-2) `= Force ………….(1)
given `P/Q = M^1 L^0 T^(-2), (ML^1 T^(-2))/(Q)= ML^0 T^(-2)`
`Q =(ML^1 T^(-2))/(ML^0 T^(-2))= L `= Displacement .......... (2)
`therefore ` P and Q are respectively the force and the displacement, hence their units are newton and metre.
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