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Given F = (a//t) + bt^2 where F denotes ...

Given `F = (a//t) + bt^2` where F denotes force and t time. The diamensions of a and b are respectively:

A

`[MLT^(-1)]` and `[MLT^(-4)]`

B

`[LT^(-1)]` and `[T^(-2)]`

C

[T] and `[T^(-2)]`

D

`[LT^(-2)]` and `[T^(-2)]`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • In a given relation F = at^2 + bt^2 , F and t denote the force and the time respectively, then dimensions of a and b are respectively as -

    A
    `M^0 L^0 T^1 , M^0 L^0 T^(-2)`
    B
    `M^0 L^1 T^(-2), M^- L^2 T^(-2)`
    C
    `M^1 L^1 T^(-3), M^1 L^1 T^(-3)`
    D
    `M^1 L^1 T^(-1), M^2 L^1 T^(-2)`

  • A force is given by F= at + bt^(2) where , t is the time .The dimensione of a and b are

    A
    `[MLT^(-4)]` and` [MLT]`
    B
    `[MLT^(-1)]` and `[MLT^(0)]`
    C
    `[MLT^(-3)] `and` [MLT^(-4)]`
    D
    `[MLT^(-3)] `and` [MLT^(0)]`

  • A force F is given by F = at + bt^(2) , where t is time. The dimensions of a and b are

    A
    `[MLT^(-3)]` and `[MLT^(-4)]`
    B
    `[MLT^(-4)]` and `[MLT^(-3)]`
    C
    `[MLT^(-1)]` and `[MLT^(-2)]`
    D
    `[MLT^(-2)]` and `[MLT^(0)]`

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