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If L = (20 +- 0.01) m and B = (10 +- 0.0...

If `L = (20 +- 0.01) m` and `B = (10 +- 0.02)m` then `L//B` is

A

`(2 pm 0.03 ) m`

B

`(2 pm 0.015 ) m`

C

`(2 pm 0.01 ) m`

D

`(2 pm 0.005 ) m`

Text Solution

Verified by Experts

The correct Answer is:
D
`(Deltax)/(x) = (DeltaL)/L + (DeltaB)/(B) implies Deltax = x[ (DeltaL)/(L) + (DeltaB)/(B)]`
`=(20)/(10) [(0.01)/(20) + (0.02)/(10)]`
`x pm Delta x = (2 pm 0.0005)m`
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