Home
Class 11
PHYSICS
The radius of a sphere is measured as (1...

The radius of a sphere is measured as `(10 +- 0.02)cm`. The error in the measurment of its volume is

A

25.lcc

B

25.12 cc

C

2.51 cc

D

251.2 cc

Text Solution

Verified by Experts

The correct Answer is:
C
`V = 4/3 pi r^3 =. (Deltav)/(v) xx100 = 3(Deltar)/(r) xx 100`
`Delta v = 3 xx (Deltar)/(r) xxv`
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise EXERCISE -I (H.W)|39 Videos

  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise EXERCISE -II (C.W)|28 Videos

  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise C.U.Q -ADDITIONAL QUESTIONS|27 Videos

  • TRANSMISSION OF HEAT

    NARAYNA|Exercise LEVEL-II(C.W)|27 Videos

  • VECTORS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

Similar Questions

Explore conceptually related problems

The radius of a sphere is measured as (10 +- 0.02%)cm . The error in the measurement of its volume is

[" The radius of a sphere is "],[" measured as "(10+-0.4%)" .The "],[" error in the measurement of "],[" its volume is "],[[" (A) "5.02cc],[" (B) "50.2cc],[" (C) "0.502cc],[" (D) "251.2cc]]

The radius fo sphere is measured as (5.2 +- 0.2)cm then the percentage error in volume of the ball is.....

The radius of a sphere is measured to be (7.50 + 0.85) cm. Suppose the percentage error in its volume is x. The value of x, to the nearest x is..........

The percentage error in measurement of radius of a sphere is 0.2% then the maximum percentage error in the measurement of its volume will be 0.6% 0.1% 0.4% 0.2%

The radius of a sphere is 8 cm and 0.02 cm is the error in its measurement. Find the approximate error in its volume.

The relative error in the measurement of the side of a cube is 0.027 The relative error in the measurement of its volume is

Error in the measurement of radius of a sphre is 1%. Then maximum percentage error in the measurement of volume is

The radius of a sphere is (5.3 +- 0.1) cm The perecentage error in its volume is

The radius of a sphere is measured to be (2.1 +- 0.02) cm . Calculate its surface area with error limits.

NARAYNA-UNITS AND MEASUREMENTS-EXERCISE -I (C.W)
  1. The length of a rod is measured as 31.52 cm. Graduations on the scale ...

    Text Solution

    |

  2. If L = (20 +- 0.01) m and B = (10 +- 0.02)m then L//B is

    Text Solution

    |

  3. The radius of a sphere is measured as (10 +- 0.02)cm. The error in the...

    Text Solution

    |

  4. If length and breath of a plate are (40 +- 0.2)cm and (30 +- 0.1 ) cm,...

    Text Solution

    |

  5. If the length of a cylinder is measured to be 4.28 cm with an error o...

    Text Solution

    |

  6. When 10 observations are taken, the random error is x, When 100 oberse...

    Text Solution

    |

  7. If L(1) = (2.02 +- 0.01)m and L(2) = (1.02 +- 0.01)m then L(1) + 2L(2)...

    Text Solution

    |

  8. A body travels unifromly a distance of (20.0 +- 0.2)m in time (4.0 +- ...

    Text Solution

    |

  9. If the value of 103.5kg is rounded off to three significant figures, t...

    Text Solution

    |

  10. The number of significant figures in 6.023xx10^(23) "mole"^(-1) is

    Text Solution

    |

  11. The side fo a cube is 2.5 metre. The volume of the cube of the signifi...

    Text Solution

    |

  12. When a force is expressed in dyne, the number of sinificant figures is...

    Text Solution

    |

  13. sqrt(2.0) is

    Text Solution

    |

  14. The mass of a box is 2.3 kg . Two marbles of masses 2.15 g and 12.48 g...

    Text Solution

    |

  15. The number of significant figures in 0.10200 is

    Text Solution

    |

  16. When the number 0.046508 is reduced to 4 significant figures, then it ...

    Text Solution

    |

  17. With due regard to significant figures, the value of (46.7-10.04) is

    Text Solution

    |

  18. The value of pi//53.2 with due regard to singificant figures is,

    Text Solution

    |

  19. By rounding off, (a) 20.96 and (b) 0.0003125 to 3 significant figures ...

    Text Solution

    |

  20. If the unit of length is doubled and that of mass and time is halved, ...

    Text Solution

    |