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A student performs exeriment with simpl...

A student performs exeriment with simple pendulum and measures time for `10` vibrations. If the measures the time for `100` vibrations, the error in measurement of time period will be reduced by a factor of......

A

10

B

90

C

100

D

1000

Text Solution

Verified by Experts

The correct Answer is:
A
`(X_1)/(X_2) = (N_2)/(N_1)`
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NARAYNA-UNITS AND MEASUREMENTS-EXERCISE -I (H.W)
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  2. If the length of a cylinder is measured to be 8.28cm with an error of ...

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  3. A student performs exeriment with simple pendulum and measures time f...

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  4. If L(1) = (3.03 +- 0.02)m and L(2) = (2.01 +- 0.02)m then L(1) + 2L(2)...

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  5. A body travels uniformly a distance of ( 13.8 +- 0.2) m in a time (4.0...

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  6. The pressure on a square plate is measured by measuring the force on t...

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  7. 2.34 is obtained by rounding off the number

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  8. The number of singnificant figures in 0.0006032 is

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  9. The radius of disc is 1.2cm its area according to idea of significant ...

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  10. When Energy is expressed in erg the no of significant figure is four. ...

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  11. sqrt(57.97) is

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  12. A stick has a length of 12.132cm and an other stick has a length of 12...

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  13. The respective number of significant figures for the numbers 23.023, 0...

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  14. The number of significiant figures in 5.69 xx 10^(15) kg is

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  15. The value of 124.2 + 52.487 with due regard to significant places is....

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  16. The value fo (9.270)/(41) with due regard to significant figures is.....

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  17. When 57.986 is rounded off to 4 significant figures, then it becomes....

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  18. If 'L' is length of sample pendulum and 'g' is acceleration due to gra...

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  19. The demensional formula for the product of two physical quantites P an...

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  20. The fundamental physical quantites that have same dimesions in the di...

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